C# Program to find Area of Triangle
Program Statement:
If the lengths of the sides of a triangle are denoted by a, b, and c, then area of triangle is given by
Area = S?S(S-a)(S-b)(S-c)
where, S = ( a + b + c ) / 2
Solution:
class sq
{
int a, b, c;
double S, Area, temp2;
public double s(double t)
{
double lb = 0, ub = t, temp = 0; int count = 50;
while (count != 0)
{
temp = (lb + ub) / 2;
if (temp * temp == t)
{ return temp; }
else if (temp * temp > t)
{ ub = temp; }
else
{ lb = temp; }
count--;
}
return temp;
}
public void cal()
{
Console.Write(" Enter value of a : ");
a = Convert.ToInt32(Console.ReadLine());
Console.Write(" Enter value of b : ");
b = Convert.ToInt32(Console.ReadLine());
Console.Write(" Enter value of c : ");
c = Convert.ToInt32(Console.ReadLine());
S = (a + b + c) / 2;
temp2 = (S * (S - a) * (S - b) * (S - c));
Area = S * s(temp2);
Console.WriteLine(" Area = {0} ", Area);
}
}
